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  2. Dell - Wikipedia

    en.wikipedia.org/wiki/Dell

    Dell dropped out of college upon completion of his freshman year at the University of Texas in order to focus full-time on his fledgling business, after getting about $1,000 in expansion-capital from his family. [16] As of April 2021, Dell's net worth was estimated to be over $50 billion (equivalent to $55,470,000,000 in 2023). [17]

  3. Year 2000 problem - Wikipedia

    en.wikipedia.org/wiki/Year_2000_problem

    Normally, a year is a leap year if it is evenly divisible by four. A year divisible by 100 is not a leap year in the Gregorian calendar unless it is also divisible by 400. For example, 1600 was a leap year, but 1700, 1800 and 1900 were not. Some programs may have relied on the oversimplified rule that "a year divisible by four is a leap year".

  4. Dell forecasts 3-4% compounded annual revenue growth over ...

    www.aol.com/news/dell-forecasts-3-4-compounded...

    Dell also said it would raise its quarterly dividend by 10% or more every year through fiscal 2028, as it plans to return more than 80% of adjusted free cash flow to shareholders through a ...

  5. Market share of personal computer vendors - Wikipedia

    en.wikipedia.org/wiki/Market_share_of_personal...

    The annual worldwide market share of personal computer vendors includes desktop computers, laptop computers, and netbooks but excludes mobile devices, such as tablet computers that do not fall under the category of 2-in-1 PCs. The global market leader has been Lenovo in every year since 2013, followed by HP and Dell.

  6. Calendar year - Wikipedia

    en.wikipedia.org/wiki/Calendar_year

    The Gregorian year, which is in use in most of the world, begins on January 1 and ends on December 31. It has a length of 365 days in an ordinary year, with 8760 hours, 525,600 minutes, or 31,536,000 seconds; but 366 days in a leap year, with 8784 hours, 527,040 minutes, or 31,622,400 seconds. With 97 leap years every 400 years, the year has an ...

  7. Birthday problem - Wikipedia

    en.wikipedia.org/wiki/Birthday_problem

    With M = 365 days in a year, the average number of people required to find a pair with the same birthday is n = 1 + Q(M) ≈ 24.61659, somewhat more than 23, the number required for a 50% chance. In the best case, two people will suffice; at worst, the maximum possible number of M + 1 = 366 people is needed; but on average, only 25 people are ...

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