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2. How can I randomly select (choose) an item from a list (get a...

   stackoverflow.com/questions/306400

   So it's not cryptographically secure (in simpler words, it's not "a secret random choice"). The second way and the third way are both cryptographically secure, but the third one uses host's operating system's random generator, while the second one is only available since Python3.6 –

3. How to randomly pick an element from an array - Stack Overflow

   stackoverflow.com/questions/8065532

   If you are going to be getting a random element multiple times, you want to make sure your random number generator is initialized only once. import java.util.Random; public class RandArray { private int[] items = new int[]{1,2,3}; private Random rand = new Random(); public int getRandArrayElement(){ return items[rand.nextInt(items.length)]; } }

4. Python random sample with a generator / iterable / iterator

   stackoverflow.com/questions/12581437

   import random def list_item(ls): for item in ls: yield item random.sample( list_item(range(100)), 20 ) UPDATE As per MartinPieters 's request I did some timing of the currently proposed three methods.

5. Creating a random item generator in java,to use in a libgdx...

   stackoverflow.com/questions/30720238

   The item just needs to have a random x positon,which is generated within the constraints of the width of the container. The game is as bottom up scroller,with different platforms being generated.

6. The relationship between Dataloader, sampler and generator in...

   stackoverflow.com/questions/74738608/the-relationship-between-dataloader...

   Let's look at all scenarios one by one. In this answer, "generator" means "random number generator" that is an instance of torch.Generator, and not Python's generator. Scenario 1. This scenario is straightforward. When one iterates a RandomSampler created without generator supplied, the

7. Getting a random value from a JavaScript array - Stack Overflow

   stackoverflow.com/questions/4550505

   As with any random function, you run the risk of getting the same value successively. If you don’t want that, you will need to track the previous value with another property: months.random=function() { var random; while((random=this[Math.floor(Math.random()*this.length)]) == this.previous); this.previous=random; return random; };

8. java - Pick a random value from an enum? - Stack Overflow

   stackoverflow.com/questions/1972392

   random() is a default extension function included in base Kotlin on the Collection object. Kotlin Documentation Link. If you'd like to simplify it with an extension function, try this: inline fun <reified T : Enum<T>> random(): T = enumValues<T>().random() // Then call random<MyEnum>() To make it static on your enum class.

9. Get a random item from a JavaScript array - Stack Overflow

   stackoverflow.com/questions/5915096

   If you really must use jQuery to solve this problem (NB: you shouldn't, but the original version of the question asked for jQuery solutions):

10. C#: Elegant code for getting a random value from an IEnumerable

    stackoverflow.com/questions/7258824

    Here's a couple extension methods for you: public static T RandomElement<T>(this IEnumerable<T> enumerable) { return enumerable.RandomElementUsing<T>(new Random()); } public static T RandomElementUsing<T>(this IEnumerable<T> enumerable, Random rand) { int index = rand.Next(0, enumerable.Count()); return enumerable.ElementAt(index); } // Usage: var ints = new int[] { 1, 2, 3 }; int randomInt ...

11. True random generation in Java - Stack Overflow

    stackoverflow.com/questions/381037

    The NSA and Intel’s Hardware Random Number Generator. To make things easier for developers and help generate secure random numbers, Intel chips include a hardware-based random number generator known as RdRand. This chip uses an entropy source on the processor and provides random numbers to software when the software requests them.