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The replace () method in python 3 is used simply by: a = "This is the island of istanbul". print (a.replace("is" , "was" , 3)) #3 is the maximum replacement that can be done in the string#. >>> Thwas was the wasland of istanbul. # Last substring 'is' in istanbul is not replaced by was because maximum of 3 has already been reached.
@kwikness - I'm pretty sure Raymond was alluding to Guido van Rossum (python's creator and BDFL (benevolent dictator for life)), Tim Peters (TimSort fame, wrote Zen of Python), and Barry Warsaw (big in python/jython - e.g., in this april fools joke Uncle Barry became FLUFL (friendly language uncle for life).
:param str string: string to execute replacements on :param dict replacements: replacement dictionary {value to find: value to replace} :rtype: str """ # Place longer ones first to keep shorter substrings from matching # where the longer ones should take place # For instance given the replacements {'ab': 'AB', 'abc': 'ABC'} against # the string ...
Python strings are immutable, you change them by making a copy. The easiest way to do what you want is probably: text = "Z" + text[1:] The text[1:] returns the string in text from position 1 to the end, positions count from 0 so '1' is the second character. edit: You can use the same string slicing technique for any part of the string
In Python string literals, backslash is an escape character. This is also true when the interactive prompt shows you the value of a string. It will give you the literal code representation of the string.
For anyone else arriving here from Google search on how to do a string replacement on all columns (for example, if one has multiple columns like the OP's 'range' column): Pandas has a built in replace method available on a dataframe object. df.replace(',', '-', regex=True) Source: Docs
With an input string of abc&def#ghi and replacing & -> \& and # -> \#, the fastest way was to chain together the replacements like this: text.replace('&', '\&').replace('#', '\#'). Timings for each function: a) 1000000 loops, best of 3: 1.47 μs per loop. b) 1000000 loops, best of 3: 1.51 μs per loop. c) 100000 loops, best of 3: 12.3 μs per loop.
Python has a built in method on strings called replace which is used as so: string.replace(old, new) So you would use: string.replace(" ", "_") I had this problem a while ago and I wrote code to replace characters in a string. I have to start remembering to check the python documentation because they've got built in functions for everything.
0. You really don't need to remove ALL the signs: lf cr crlf. # Pythonic: r'\n', r'\r', r'\r\n'. Some texts must have breaks, but you probably need to join broken lines to keep particular sentences together. Therefore it is natural that line breaking happens after priod, semicolon, colon, but not after comma.
All string characters are unicode literal in Python 3; as a consequence, since str.split() splits on all white space characters, that means it splits on unicode white space characters. So split + join syntax (as in 1 , 2 , 3 ) will produce the same output as re.sub with the UNICODE flag (as in 4 ); in fact, the UNICODE flag is redundant here ...